`underset((ii) H_(2)O)overset((i) CO_(2))(rarr)` In the reaction, product P is

Options

A.
B.
C.
D. `C_(6)H_(5) - overset(O)overset(||)(C ) - C_(6) H_(5)`

Explanation

To solve the problem, we need to analyze the reaction of phenylmagnesium bromide (a Grignard reagent) with carbon dioxide (CO2) and water (H2O). Let's break it down step by step:

### Step 1: Identify the Grignard Reagent
The given Grignard reagent is phenylmagnesium bromide, which can be represented as C6H5MgBr. Here, C6H5 (the phenyl group) is the organic part, and MgBr is the metal part.

**Hint:** Remember that Grignard reagents are highly reactive and can act as nucleophiles due to the presence of a carbon atom with a partial negative charge.

### Step 2: Reaction with Carbon Dioxide
When phenylmagnesium bromide reacts with carbon dioxide (CO2), the nucleophilic carbon (C6H5-) attacks the electrophilic carbon of CO2. The structure of CO2 is O=C=O, where the central carbon is electrophilic.

**Hint:** Look for the electrophilic center in CO2 that can be attacked by the nucleophile.

### Step 3: Formation of the Intermediate
The attack of the phenyl group on CO2 leads to the formation of a carboxylate intermediate. The reaction can be visualized as follows:

1. The phenyl group (C6H5-) attacks the carbon of CO2.
2. This results in the formation of a compound with a carboxylate group (-COO-) and the magnesium bromide complex.

The structure can be represented as:
\[ C6H5-C(=O)O^{-}MgBr^{+} \]

**Hint:** The product formed after the nucleophilic attack will contain a carboxylate group.

### Step 4: Hydrolysis with Water
In the next step, the carboxylate intermediate reacts with water (H2O). The water molecule donates a proton (H+) to the carboxylate oxygen, leading to the formation of a carboxylic acid.

The reaction can be summarized as:
\[ C6H5-C(=O)O^{-} + H2O \rightarrow C6H5-C(=O)OH + MgBrOH \]

The final product is benzoic acid (C6H5COOH).

**Hint:** Remember that hydrolysis of the carboxylate ion will yield the corresponding carboxylic acid.

### Step 5: Conclusion
The product P formed from the reaction of phenylmagnesium bromide with CO2 and water is benzoic acid (C6H5COOH).

**Final Answer:** The product P is benzoic acid (C6H5COOH).