`2CH_(3) "COOH" underset(300^(@) C )overset(MnO)(rarr) A`, product 'A ' in the reaction is

Options

A. `CH_(3) CH_(2)` CHO
B. `CH_(3) - CH_(2) `- OH
C. `CH_(3)"COCH"_(3)`
D. `CH_(3) - underset(O)underset(||)(C ) -O- underset(O)underset(||)(C ) - CH_(3)`

Explanation

To determine the product 'A' formed when two moles of acetic acid (CH₃COOH) are heated at 300°C in the presence of manganese dioxide (MnO), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
We start with two moles of acetic acid, which has the formula CH₃COOH.

2. **Understand the Reaction Conditions**:
The reaction is conducted at a high temperature (300°C) and involves MnO, which acts as an oxidizing agent.

3. **Analyze the Reaction**:
When acetic acid is heated in the presence of MnO, it undergoes dehydration and oxidation. The reaction can lead to the formation of ketones.

4. **Dehydration of Acetic Acid**:
The dehydration of acetic acid can lead to the formation of acetone (propanone). The reaction can be summarized as:
\[ 2 \text{CH}_3\text{COOH} \rightarrow \text{CH}_3\text{COCH}_3 + \text{CO}_2 + \text{H}_2\text{O} \]
Here, the acetic acid loses water (H₂O) and carbon dioxide (CO₂), resulting in the formation of acetone (CH₃COCH₃).

5. **Identify the Product**:
The product 'A' formed from this reaction is acetone (propanone), which is represented by the formula CH₃COCH₃.

### Final Answer:
The product 'A' in the reaction is **acetone (CH₃COCH₃)**.

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