A compound (X) `C_(4)H_(8)`O Which gives a 2,4-DNP derivative and a positive iodoform test is:

Options

A. `CH_(3) -CH_(2) - overset(O)overset(||)(C ) - CH_(3)`
B. `CH_(3) - CH_(2) -CH_(2)-`CHO
C. `CH_(3)- underset(CH_(3))underset(|)(CH) -`CHO
D. All of these

Explanation

To solve the problem, we need to identify the compound (X) with the molecular formula C4H8O that gives a 2,4-DNP derivative and a positive iodoform test. Let's break down the steps:

### Step 1: Analyze the Molecular Formula
The compound has the molecular formula C4H8O. This indicates that it could be either a ketone or an aldehyde.

**Hint:** Look for functional groups that can fit the molecular formula C4H8O.

### Step 2: Identify the Functional Groups
Since the compound gives a positive iodoform test, it must contain a methyl ketone group (–COCH3). This is a key requirement for the iodoform test, which is positive for compounds that have the structure RCOCH3, where R can be any alkyl group.

**Hint:** Remember that the iodoform test is specific for methyl ketones.

### Step 3: Determine Possible Structures
Given that the compound is C4H8O and must contain a methyl ketone, we can deduce that the structure must be a ketone. The possible structure that fits this description is 3-pentanone (or 2-butanone), which has the methyl group adjacent to the carbonyl group.

**Hint:** Draw out possible structures for C4H8O that include a methyl ketone.

### Step 4: Confirm the 2,4-DNP Test
The 2,4-DNP (2,4-dinitrophenylhydrazine) test is used to identify carbonyl compounds (aldehydes and ketones). When a ketone or aldehyde reacts with 2,4-DNP, it forms a yellow-orange precipitate. Since we have identified that our compound is a ketone, it will react with 2,4-DNP to form a derivative.

**Hint:** Recall that the formation of a yellow-orange precipitate indicates the presence of a carbonyl group.

### Step 5: Conclusion
Based on the above analysis, the compound (X) is likely to be 2-butanone (or 3-pentanone) since it meets all the criteria: it has the molecular formula C4H8O, gives a positive iodoform test due to the presence of a methyl ketone, and forms a 2,4-DNP derivative.

**Final Answer:** The compound (X) is 2-butanone (or 3-pentanone).