Compound 'X' `(C_(4)H_(8) O_(2))` is a sweet smelling liquid. It gives negative tests with Na Metal, `"NaHCO"_(3)` and 2,4-DNP. Its another isomer 'Y' responds positively to 2,4-DNP and iodoform test, but negatively to Na metal and ` "NaHCO"_(3)` Identify X and Y

Options

A. `{:("Compound X",,"Isomer Y"),(H - overset(O)overset(||)(C) - OC_(3) H_(7),,CH_(3)-overset(O)overset(||)(C)-OC_(2)H_(5)):}`
B. `{:("Compound X",,"Isomer Y"),(CH_(3) - overset(O)overset(||)(C) - OC_(2) H_(5),,C_(2)H_(5)-overset(O)overset(||)(C)-OCH_(2)):}`
C. `{:("Compound X",,"Isomer Y"),(C_(2)H_(5) - overset(O)overset(||)(C) - OCH_(3),,CH_(3)-overset(O)overset(||)(C)-CH_(2)-OCH_(3)):}`
D. `{:("Compound X",,"Isomer Y"),(CH_(3) - overset(O)overset(||)(C) - OC_(2) H_(5),,C_(3)H_(7)-overset(O)overset(||)(C)-OH):}`

Explanation

To solve the problem, we need to identify the compounds X and Y based on the provided information.

### Step 1: Analyze Compound X
- **Given Information**: Compound X has the molecular formula \(C_4H_8O_2\), is a sweet-smelling liquid, and gives negative tests with sodium metal, sodium bicarbonate (NaHCO3), and 2,4-DNP.
- **Interpretation**:
- Negative test with sodium metal indicates that there are no acidic hydrogens (like those found in alcohols or carboxylic acids).
- Negative test with NaHCO3 indicates that there is no carboxylic acid group present.
- Negative test with 2,4-DNP indicates that there is no carbonyl group (neither aldehyde nor ketone).

### Conclusion for X:
Since X does not have any acidic hydrogen, carboxylic acid group, or carbonyl group, it must be an ester.

### Step 2: Analyze Compound Y
- **Given Information**: Compound Y is another isomer of X, has the same molecular formula \(C_4H_8O_2\), responds positively to 2,4-DNP and the iodoform test, but negatively to sodium metal and NaHCO3.
- **Interpretation**:
- Positive test with 2,4-DNP indicates the presence of a carbonyl group (either a ketone or an aldehyde).
- Positive iodoform test indicates the presence of a methyl ketone group (a ketone with at least one methyl group adjacent to the carbonyl).
- Negative tests with sodium metal and NaHCO3 indicate that there are no acidic hydrogens present.

### Conclusion for Y:
Since Y has a carbonyl group and a methyl ketone, it must be a ketone.

### Step 3: Identify Compounds X and Y
- **Identifying X**: Since X is an ester, we can suggest a possible structure such as ethyl acetate (\(C_2H_5COOCH_3\)).
- **Identifying Y**: Since Y is a methyl ketone, a possible structure could be 3-pentanone.

### Final Answer:
- **Compound X**: Ethyl acetate (or another ester).
- **Compound Y**: 3-pentanone (or another methyl ketone).