Arrange the following polymers in increasing order of their intermolecular forces :
(i) Nylon 6, 6, Buna-S, Polythene.
(ii) Nylon 6, Neoprene, Polyvinyl chloride.

Options

A. II,I,III
B. III,II,I
C. I,II,III
D. II,III,I

Answer

C

Explanation

Nylon-66 is a fibre and has hydrogen bonding as intermolecular force . Buna-S ia an elastomer and has weak van der Waal.s forces . Polythene is thermoplastic and has intermediate intermolecular forces (i.e. , stronger than elastomer but weaker than fibre ) .
Thus the order of intermolecular forces is Buna-S ` lt ` polythene ` lt` Nyon-66
`(II)" "(III)" "(I)`