If `alpha,beta` are the zeros of the polynomial `p(x) = x^2 -a(x+1)-b` such that `(alpha+1)(beta+1) = 0 ` then find value of b

If alpha, beta are the zeros of polynomial f(x) = x^(2) - p(x+1)-c then (alpha + 1) (beta +1 ) = …………

If alpha,\ beta are the zeros of the polynomial f(x)=x^2-p(x+1)-c such that (alpha+1)(beta+1)=0 , then c= (a) 1 (b) 0 (c) -1 (d) 2

If alpha,beta are the zeros of the polynomial f(x)=x^(2)-p(x+1)-c such that (alpha+1)(beta+1)=0, then c=( a )1(b)0(c)-1(d)2

If alpha, beta are the zeros of the polynomial f(x) = x^2 – 3x + 2 , then find 1/alpha + 1/beta .

If alpha, beta are the zeroes of the polynomial f(x) = x^2+x+1 , then 1/alpha+1/beta =

If alpha, beta are the zeroes of the polynomial f(x)= x^2+x+1 , then (alpha+1)(beta+1) =

If alpha,beta are the zeroes of the polynomial x^(2)-p(x+1)-q , then (alpha+1)(beta+1)=

If alpha and beta are the zeroes of polynomial f(x)=x^(2)-p(x+1)-c then the value of (alpha+1)(beta+1)

If alpha,beta are the zeroes of polynomial f(x)=x^2-p(x+1)-c ,then (alpha+1)(beta+1) =

If alpha and beta are the zeros of the quadratic polynomial f(x)=x^2-p(x+1)-c , show that (alpha+1)(beta+1)=1-c .