A particle moves according to the law `x=t^(3)-6t^(2)+9t+5`. The displacement of the particle at the time when its acceleration is zero, is

A particle moves according to the law s= t^3-6t^2+9t +5 . The displacement of the particle at the time when its acceleration is zero is........ A) 9 B) -7 C) 7 D) 0

A particle moves according to the law s=t^3-6t^2+9t+ 15 . Find the velocity when t=0 .

A particle moves along x-axis according to the law x=(t^(3)-3t^(2)-9t+5)m . Then :-

A particle moves according to law s=t^(3)-6t^(2)+9t+15 . Find the velocity when t = 0.

A particle moves according to the law s=t^(3)-9t^(2)+24t . The distance covered by the particle before it first comes to rest is -

A particle is moving along a line according to the law s=t^3-3t^2+5 . The acceleration of the particle at the instant where the velocity is zero is

A particle moves according to law s=t^3-3t^2+3t+12 . The velocity when the acceleration is zero is

The distances moved by a particle in time t seconds is given by s=t^(3)-6t^(2)-15t+12 . The velocity of the particle when acceleration becomes zero, is

The distances moved by a particle in time t seconds is given by s=t^(3)-6t^(2)-15t+12 . The velocity of the particle when acceleration becomes zero, is

For a particle moving in a straight line, the displacement of the particle at time t is given by S=t^(3)-6t^(2) +3t+7 What is the velocity of the particle when its acceleration is zero?