`log_3 2, log_6 2, log_12 2` are in

log_3 2 , log_6 2 and log_12 2 are in

log_(3)^(2), log_(6)^(2), log_(120^(2) are in

log_(3)(2),log_(6)(2) and log_(12)(2) are in

Let x=(anti log_2 3)*log_3 2, y=log_2(log_3 512))"and"z=log_5 3*log_7 5*log_2 7, then xyz is equal to

The solution set of the system of equations log_12 x(1/(log_x 2)+log_2 y)=log_2 x and log_2 x.(log_3(x+y))=3 log_3 x is : (i) x=6, y=2 (ii) x=4, y=3 (iii) x=2, y=6 (iv) x=3, y=4

The solution set of the system of equations log_12 x(1/(log_x 2)+log_2 y)=log_2 x and log_2 x.(log_3(x+y))=3 log_3 x is : (i) x=6, y=2 (ii) x=4, y=3 (iii) x=2, y=6 (iv) x=3, y=4

Delta=|[log x ,log y, log z],[log 2 x, log 2 y, log 2 z],[log 3 x, log 3 y, log 3 z ]|=

If 3(log 5 - log 3) - (log 5 - 2 log 6) = 2 - log x, find x.

If log_2 (log_2 (log_3 x)) = log_2 (log_3 (log_2 y))=0 , then the value of (x+y) is

Given 3 (log 5 - log 3 ) - ( log 5 - 3 log 6 ) = 2- log m, find m.