Match column-I with column-II and select the correct option from the codes given below.
Column -I Column-II
A Tetrose sugar (i)Galactose
B Pentose sugar (ii) Maltose
C Hexose sugar (iii) Erythrose
D Disaccharide (iv) Ribose (v)Sedoheptulose

Options

A. A-(v),B-(iv),C-(iii),D-(i),(ii)
B. A-(iii),B-(iv),C-(v),D-(ii)
C. A-(iii),B-(iv),C-(i),D-(ii)
D. A-(i),(ii),B-(iv),C-(iii),D-(v)

Answer

To solve the matching question between Column-I and Column-II, we need to identify the correct pairs based on the definitions of the sugars and their structures. Here’s a step-by-step breakdown of the solution:

### Step 1: Identify Tetrose Sugar
- **Definition**: Tetrose sugar is a sugar that contains 4 carbon atoms.
- **Options**: In Column-II, we have:
- (i) Galactose (6 carbon atoms)
- (ii) Maltose (12 carbon atoms)
- (iii) Erythrose (4 carbon atoms)

**Match**: A (Tetrose sugar) matches with (iii) Erythrose.

### Step 2: Identify Pentose Sugar
- **Definition**: Pentose sugar is a sugar that contains 5 carbon atoms.
- **Options**: In Column-II, we have:
- (iv) Ribose (5 carbon atoms)

**Match**: B (Pentose sugar) matches with (iv) Ribose.

### Step 3: Identify Hexose Sugar
- **Definition**: Hexose sugar is a sugar that contains 6 carbon atoms.
- **Options**: In Column-II, we have:
- (i) Galactose (6 carbon atoms)

**Match**: C (Hexose sugar) matches with (i) Galactose.

### Step 4: Identify Disaccharide
- **Definition**: Disaccharide is a carbohydrate that contains two monosaccharide units.
- **Options**: In Column-II, we have:
- (ii) Maltose (which is made from two glucose units)

**Match**: D (Disaccharide) matches with (ii) Maltose.

### Summary of Matches:
- A (Tetrose sugar) → (iii) Erythrose
- B (Pentose sugar) → (iv) Ribose
- C (Hexose sugar) → (i) Galactose
- D (Disaccharide) → (ii) Maltose

### Final Matching:
- A → iii
- B → iv
- C → i
- D → ii

### Conclusion:
The correct option from the codes given below would be:
- A → iii
- B → iv
- C → i
- D → ii