What will the formula of a polysaccharide formed by the condensation of 60 ribose sugar units.

Options

A. `C_(300)H_(600) O_(300)`
B. `C_(300)H_(480)O_(240)`
C. `C_(300)H_(482)O_(241)`
D. `C_(300)H_(478)O_(238)`

Answer

To determine the formula of a polysaccharide formed by the condensation of 60 ribose sugar units, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Formula of Ribose**:
The molecular formula of ribose is C₅H₁₀O₅.

2. **Calculate the Total Number of Atoms in 60 Ribose Units**:
- For 60 ribose sugar units, the total number of carbon (C), hydrogen (H), and oxygen (O) atoms can be calculated as follows:
- Carbon: 60 × 5 = 300
- Hydrogen: 60 × 10 = 600
- Oxygen: 60 × 5 = 300

Therefore, without considering the condensation, we have:
- C = 300
- H = 600
- O = 300

3. **Account for Water Molecules Lost During Condensation**:
- When 60 ribose units condense, 59 water molecules (H₂O) are released (since each condensation reaction between two sugars releases one water molecule).
- Each water molecule consists of 2 hydrogen atoms and 1 oxygen atom.

4. **Calculate the Total Atoms After Condensation**:
- **Hydrogen**:
- Initial H = 600
- Water lost = 59 × 2 = 118
- Remaining H = 600 - 118 = 482
- **Oxygen**:
- Initial O = 300
- Water lost = 59
- Remaining O = 300 - 59 = 241

5. **Final Molecular Formula**:
After accounting for the loss of water, the final molecular formula for the polysaccharide formed by the condensation of 60 ribose sugar units is:
- C₃₀₀H₄₈₂O₂₄₁

### Final Answer:
The formula of the polysaccharide formed by the condensation of 60 ribose sugar units is C₃₀₀H₄₈₂O₂₄₁.