Mark the mismatched pair,

Options

A. Cellulose: Unbranched polymer with `beta` , 1-4 glycosidic linkage
B. Cellophane: Cellulose xanthate
C. Cellophane: Exopeptidase, `Mg_(2+)` acts as a co-factor
D. Aminopeptidase: Exopeptidase, cleaves the peptide bond at N- terminal end

Answer

To identify the mismatched pair from the given options, we will analyze each option step by step.

### Step 1: Analyze the first pair - Cellulose
- **Statement**: Cellulose is an unbranched polymer with beta-1,4 glycosidic linkages.
- **Analysis**: This statement is true. Cellulose is indeed an unbranched polysaccharide made up of β-1,4-glycosidic linkages between glucose units.

### Step 2: Analyze the second pair - Cellophane and Cellulose Xanthate
- **Statement**: Cellophane is chemically similar to cellulose xanthate.
- **Analysis**: This statement is also true. Cellophane is derived from cellulose and is chemically similar to cellulose xanthate, which is a derivative of cellulose.

### Step 3: Analyze the third pair - Cellophane and Exopeptidase
- **Statement**: Cellophane is an exopeptidase and Mg²⁺ acts as a cofactor.
- **Analysis**: This statement is incorrect. Cellophane is not an enzyme; it is a regenerated form of cellulose used in packaging. Exopeptidases are enzymes that break down peptides into amino acids, and while Mg²⁺ can act as a cofactor for some enzymes, it does not apply to cellophane.

### Step 4: Analyze the fourth pair - Aminopeptidase
- **Statement**: Aminopeptidase is an exopeptidase that cleaves peptide bonds from the N-terminal.
- **Analysis**: This statement is true. Aminopeptidase is indeed an exopeptidase that removes amino acids from the N-terminal end of peptides.

### Conclusion
After analyzing all the pairs, we find that the mismatched pair is:
- **Cellophane is an exopeptidase** (This is incorrect).

Thus, the answer is option C.

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