The ratio between the number of chromatids in metaphase cell and the number of chromosomes moving to each pole during anaphase of mitosis is

Options

A. ` 1:1`
B. `1:2`
C. ` 2:1`
D. ` 4:1`

Answer

To find the ratio between the number of chromatids in a metaphase cell and the number of chromosomes moving to each pole during anaphase of mitosis, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Stages of Mitosis:**
- In **metaphase**, chromosomes are aligned at the metaphase plate, and each chromosome consists of two sister chromatids joined at the centromere.
- In **anaphase**, the sister chromatids are separated and move towards opposite poles of the cell.

2. **Counting Chromatids in Metaphase:**
- Let's assume that there are **4 chromatids** in a metaphase cell. This means there are 2 chromosomes (since each chromosome has 2 chromatids).
- Therefore, the number of chromatids in the metaphase cell = **4**.

3. **Counting Chromosomes in Anaphase:**
- During anaphase, when the chromatids are separated, each chromatid is now considered an individual chromosome.
- Since we had 4 chromatids in metaphase, after separation, there will be **4 chromosomes** (2 on each pole).
- Thus, the number of chromosomes moving to each pole = **2** (since the total of 4 chromosomes is divided equally between the two poles).

4. **Calculating the Ratio:**
- Now, we can calculate the ratio of the number of chromatids in metaphase to the number of chromosomes moving to each pole during anaphase.
- This ratio is calculated as:
\[ \text{Ratio} = \frac{\text{Number of chromatids in metaphase}}{\text{Number of chromosomes moving to each pole}} = \frac{4}{2} = 2 \]
- Therefore, the ratio is **2:1**.

5. **Conclusion:**
- The final answer to the question is that the ratio between the number of chromatids in a metaphase cell and the number of chromosomes moving to each pole during anaphase of mitosis is **2:1**.