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Minimum number of meiotic divisions requ...

Minimum number of meiotic divisions required to produce 100 wheat grains are

A

400

B

25

C

200

D

20

Text Solution

AI Generated Solution

The correct Answer is:
To determine the minimum number of meiotic divisions required to produce 100 wheat grains, we need to consider the formation of male and female gametes through meiosis. Here’s a step-by-step breakdown of the solution: ### Step 1: Understand the Process of Meiosis Meiosis is a type of cell division that reduces the chromosome number by half, resulting in the formation of gametes (sperm and egg cells). In wheat, which is a diploid organism (2n), meiosis occurs in the microspore mother cells (for male gametes) and megaspore mother cells (for female gametes). ### Step 2: Calculate Male Gametes 1. **Male Gamete Formation**: Each meiotic division in a microspore mother cell produces 4 microspores (male gametes). 2. **Required Male Gametes**: To produce 100 wheat grains, we need 100 male gametes. 3. **Meiotic Divisions for Male Gametes**: Since 1 meiotic division produces 4 microspores, to find the number of meiotic divisions needed for 100 male gametes, we calculate: \[ \text{Number of meiotic divisions} = \frac{100 \text{ male gametes}}{4 \text{ microspores per meiosis}} = 25 \] ### Step 3: Calculate Female Gametes 1. **Female Gamete Formation**: Each meiotic division in a megaspore mother cell produces 4 megaspores, but only 1 of these becomes a functional female gamete (the other 3 are non-functional). 2. **Required Female Gametes**: To produce 100 wheat grains, we need 100 female gametes. 3. **Meiotic Divisions for Female Gametes**: Since only 1 functional megaspore is produced from each meiotic division, we need: \[ \text{Number of meiotic divisions} = 100 \text{ female gametes} = 100 \] ### Step 4: Total Meiotic Divisions Now, we can calculate the total number of meiotic divisions required: \[ \text{Total meiotic divisions} = \text{Meiotic divisions for male gametes} + \text{Meiotic divisions for female gametes} = 25 + 100 = 125 \] ### Conclusion The minimum number of meiotic divisions required to produce 100 wheat grains is **125**.
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