What is the D.P.D of cell ,which Is having osmotic pressure of 9 bars and turgor pressure 6 bars?

Answer

To find the Diffusion Pressure Deficit (DPD) of a cell, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Definitions**:
- **Osmotic Pressure (OP)**: This is the pressure required to prevent the flow of water across a semipermeable membrane due to osmosis. In this case, the osmotic pressure is given as 9 bars.
- **Turgor Pressure (TP)**: This is the pressure exerted by the fluid (usually water) inside the cell against the cell wall. Here, the turgor pressure is given as 6 bars.
- **Diffusion Pressure Deficit (DPD)**: This is calculated as the difference between osmotic pressure and turgor pressure.

2. **Write the Formula for DPD**:
\[ \text{DPD} = \text{Osmotic Pressure (OP)} - \text{Turgor Pressure (TP)} \]

3. **Substitute the Given Values**:
- Given that OP = 9 bars and TP = 6 bars, substitute these values into the formula:
\[ \text{DPD} = 9 \text{ bars} - 6 \text{ bars} \]

4. **Perform the Calculation**:
\[ \text{DPD} = 3 \text{ bars} \]

5. **Conclusion**:
- The Diffusion Pressure Deficit (DPD) of the cell is 3 bars.

### Final Answer:
The DPD of the cell is **3 bars**.

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