If 36 `CO_(2)` molecules are fixed in `C_(3)` plant what will be a The number of G-3P and b) Erythrose-4-phosphate formed during the dark reaction

Options

A. a=144, b=24
B. a=144,b=28
C. a=72,b=14
D. a=72,b=12

Answer

To solve the problem of how many G3P (Glyceraldehyde-3-phosphate) and Erythrose-4-phosphate are formed when 36 CO2 molecules are fixed in a C3 plant, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Basic Conversion**:
- In the Calvin cycle (dark reaction) of C3 plants, 3 CO2 molecules are required to produce 1 Erythrose-4-phosphate (E4P) and 6 G3P molecules.

2. **Calculate Erythrose-4-phosphate (E4P)**:
- Since 3 CO2 molecules yield 1 E4P, we can find out how many E4P are produced from 36 CO2 molecules.
- Calculation:
\[ \text{E4P} = \frac{36 \text{ CO2}}{3 \text{ CO2/E4P}} = 12 \text{ E4P} \]

3. **Calculate G3P**:
- From the same 3 CO2 molecules, we also know that they yield 6 G3P.
- Calculation:
\[ \text{G3P} = \frac{36 \text{ CO2}}{3 \text{ CO2}} \times 6 \text{ G3P} = 12 \times 6 = 72 \text{ G3P} \]

4. **Summarize the Results**:
- **a)** The number of G3P formed is 72.
- **b)** The number of Erythrose-4-phosphate formed is 12.

### Final Answer:
- a) G3P = 72
- b) Erythrose-4-phosphate = 12