If `24CO_(2)` molecules are fixed in `C_(3)` plants whats will the number of (1)G-3P(2) erythorose phosphate (3) xylulose phosphate (4) sedophetulose 7 phsophate molecules formed
`{:(A,B,C,D),(72,12,24,8),(48,8,16,8),(72,12,24,12),(48,16,8,8):}`

Answer

To solve the problem of how many molecules of G-3P, erythrose phosphate, xylulose phosphate, and sedoheptulose 7 phosphate are formed when 24 CO2 molecules are fixed in C3 plants, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Calvin Cycle**:
- The Calvin cycle is the process by which CO2 is fixed in C3 plants. For every 3 CO2 molecules fixed, specific products are formed.

2. **Products from 3 CO2 Molecules**:
- From the video transcript, we know that when 3 CO2 molecules are fixed, the following products are formed:
- G-3P (Glyceraldehyde 3-phosphate): 6 molecules
- Erythrose phosphate: 2 molecules
- Xylulose phosphate: 4 molecules
- Sedoheptulose 7 phosphate: 1 molecule

3. **Scaling Up to 24 CO2 Molecules**:
- Since we need to find the number of products formed from 24 CO2 molecules, we can set up a proportion based on the products formed from 3 CO2 molecules.
- To find the number of products from 24 CO2 molecules, we multiply the number of products formed from 3 CO2 by the factor of 8 (since 24 is 8 times 3).

4. **Calculating Each Product**:
- G-3P: \(6 \times 8 = 48\)
- Erythrose phosphate: \(2 \times 8 = 16\)
- Xylulose phosphate: \(4 \times 8 = 32\)
- Sedoheptulose 7 phosphate: \(1 \times 8 = 8\)

5. **Final Counts**:
- Therefore, the number of molecules formed from 24 CO2 molecules is:
- G-3P: 48
- Erythrose phosphate: 16
- Xylulose phosphate: 32
- Sedoheptulose 7 phosphate: 8

### Final Answer:
- The final counts are:
- G-3P: 48
- Erythrose phosphate: 16
- Xylulose phosphate: 32
- Sedoheptulose 7 phosphate: 8