In yeast during anaerobic respiration, how many glucose molecules are required for production of 38 ATP molecules?

Options

A. 1
B. 2
C. 19
D. 38

Answer

To determine how many glucose molecules are required for the production of 38 ATP molecules during anaerobic respiration in yeast, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Anaerobic Respiration Process in Yeast**:
- In yeast, during anaerobic respiration (fermentation), one molecule of glucose is converted into two molecules of pyruvate.

2. **ATP Production from Glucose**:
- During the conversion of glucose to pyruvate, a total of 2 ATP molecules are produced. Therefore, from one molecule of glucose, we get 2 ATP.

3. **Calculate the Number of Glucose Molecules Needed**:
- To find out how many glucose molecules are needed to produce 38 ATP molecules, we can set up a simple equation:
- If 1 glucose → 2 ATP
- Let \( x \) be the number of glucose molecules needed to produce 38 ATP:
\[ 2x = 38 \]

4. **Solve for \( x \)**:
- Divide both sides of the equation by 2:
\[ x = \frac{38}{2} = 19 \]

5. **Conclusion**:
- Therefore, 19 glucose molecules are required to produce 38 ATP molecules during anaerobic respiration in yeast.

### Final Answer:
19 glucose molecules are required for the production of 38 ATP molecules in yeast during anaerobic respiration.