Heterozygous tall (Tt) and dwarf (tt) Pea plants are crossed . The ratio in the offspring shall be

Options

A. All tall
B. All dwarf
C. 3 tall : 1 dwarf
D. 1 tall : 1 dwarf

Answer

To solve the problem of crossing a heterozygous tall pea plant (Tt) with a dwarf pea plant (tt), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Genotypes**:
- The heterozygous tall plant has the genotype Tt (where T is the dominant allele for tallness and t is the recessive allele for dwarfness).
- The dwarf plant has the genotype tt.

2. **Determine the Gametes**:
- The Tt plant can produce two types of gametes: T (tall) and t (dwarf).
- The tt plant can only produce one type of gamete: t (dwarf).

3. **Set Up the Punnett Square**:
- Create a Punnett square to visualize the possible combinations of alleles from the parents.
- The rows will represent the gametes from the Tt parent (T and t), and the columns will represent the gametes from the tt parent (t).

| | t | t |
|-------|-------|-------|
| **T** | Tt | Tt |
| **t** | tt | tt |

4. **Fill in the Punnett Square**:
- The combinations from the Punnett square show:
- Tt (heterozygous tall) from T and t
- Tt (heterozygous tall) from T and t
- tt (dwarf) from t and t
- tt (dwarf) from t and t

5. **Count the Offspring Ratios**:
- From the Punnett square, we see that there are:
- 2 Tt (tall)
- 2 tt (dwarf)
- This gives us a ratio of 2 tall plants to 2 dwarf plants, which simplifies to 1 tall : 1 dwarf.

6. **Conclusion**:
- Therefore, the ratio of tall to dwarf offspring from this cross is 1:1.

### Final Answer:
The ratio in the offspring shall be 1 tall : 1 dwarf.

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