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The recombinant phenotypic ratio in F(2)...

The recombinant phenotypic ratio in `F_(2)` obtained from parental cross having genotypes TTRR x ttrr will be

A

9 : 3 : 3 : 1

B

`3 : 1`

C

`1 : 2 : 1`

D

`3 : 3`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the recombinant phenotypic ratio in the F2 generation from the parental cross TTRR x ttrr, we can follow these steps: ### Step-by-Step Solution: 1. **Identify Parent Genotypes and Traits:** - The parental genotypes are TTRR (tall, round seeds) and ttrr (dwarf, wrinkled seeds). - T (tall) is dominant over t (dwarf), and R (round) is dominant over r (wrinkled). 2. **Determine Gametes from Parents:** - The gametes produced by TTRR will be TR. - The gametes produced by ttrr will be tr. - Therefore, the F1 generation will consist of all offspring having the genotype TtRr (tall, round seeds). 3. **Selfing the F1 Generation:** - When we self the F1 generation (TtRr x TtRr), we can use a Punnett square to determine the F2 generation. 4. **Constructing a Punnett Square:** - The gametes from TtRr will be TR, Tr, tR, and tr. - Setting up the Punnett square will give us a 4x4 grid. 5. **Filling in the Punnett Square:** - The resulting genotypes from the Punnett square will be: - TTRR (Tall, Round) - TTRr (Tall, Round) - TtRR (Tall, Round) - TtRr (Tall, Round) - TtRr (Tall, Round) - Ttrr (Tall, Wrinkled) - ttRR (Dwarf, Round) - ttRr (Dwarf, Round) - ttrr (Dwarf, Wrinkled) 6. **Counting Phenotypes:** - The phenotypic ratio can be summarized as follows: - Tall Round (T_R): 9 (TTRR, TTRr, TtRR, TtRr) - Tall Wrinkled (T_rr): 3 (Ttrr) - Dwarf Round (ttR_): 3 (ttRR, ttRr) - Dwarf Wrinkled (ttrr): 1 (ttrr) 7. **Identifying Recombinant Phenotypes:** - The recombinant phenotypes are those that differ from the parents: - Tall Wrinkled (T_rr) and Dwarf Round (ttR_). - Thus, the recombinant phenotypes are 3 (Tall Wrinkled) + 3 (Dwarf Round) = 6. 8. **Calculating the Recombinant Phenotypic Ratio:** - The total number of phenotypes in F2 is 16 (9 + 3 + 3 + 1). - The recombinant phenotypic ratio is therefore 6 out of 16, which simplifies to 3:3 or 1:1. ### Final Answer: The recombinant phenotypic ratio in F2 generation is **3:3**.
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