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In maize, coloured endosperm (C) is dom...

In maize, coloured endosperm (C) is dominated over colourless (C) and full endosperm (R) is dominan over shrunken (r) . When a dihybrid of `F_(1)` generationwas test crossed it produced four phenoypes in the following percentage
Coloured and Full - 45%
Coloured - Shrunken - 5%
Coloured - Full - 4%
Coloured -Shrunken - 16%
From these date what would be distance between the two non allelic genes

A

48 unit

B

9 unit

C

4 unit

D

12 unit

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem regarding the distance between two non-allelic genes in maize, we will follow these steps: ### Step 1: Identify the Dominant and Recessive Traits In maize, we have the following traits: - Colored endosperm (C) is dominant over colorless endosperm (c). - Full endosperm (R) is dominant over shrunken endosperm (r). ### Step 2: Understand the Dihybrid Cross A dihybrid cross involves two traits. In this case, we are crossing plants that are heterozygous for both traits (C/c and R/r). The F1 generation will have the genotype CcRr. ### Step 3: Perform a Test Cross The F1 generation (CcRr) is test crossed with a homozygous recessive individual (ccrr). This will yield the following possible gametes from the F1 generation: - CR - Cr - cR - cr ### Step 4: Analyze the Phenotypic Ratios The test cross produces four phenotypes with the following percentages: - Colored and Full (C_R): 45% - Colored and Shrunken (C_rr): 5% - Colorless and Full (ccR): 4% - Colorless and Shrunken (ccrr): 16% ### Step 5: Identify Parental and Recombinant Types From the data: - Parental types (non-recombinant): Colored and Full (45%) and Colorless and Shrunken (16%). - Recombinant types: Colored and Shrunken (5%) and Colorless and Full (4%). ### Step 6: Calculate the Total Number of Recombinants Total recombinant frequency = Colored and Shrunken (5%) + Colorless and Full (4%) = 9%. ### Step 7: Calculate the Distance Between the Genes The distance between the two non-allelic genes (C and R) is calculated as: - Distance = Total recombinant frequency = 9%. ### Step 8: Convert to Centimorgans In genetics, 1% recombination frequency is equivalent to 1 centimorgan (cM). Therefore, the distance is: - Distance = 9% = 9 centimorgans. ### Final Answer The distance between the two non-allelic genes is **9 centimorgans**. ---
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