Eccentricity of the conic represented by x =e + e-a, y = ea-e-aiS2/3

Let e be the eccentricity of the ellipse represented by x=5 (2cos theta+3 sin theta) , y =4 (2 sin theta -3 cos theta ), then e^2 equals

The eccentricity of the conic represented by sqrt((x+2)^(2)+y^(2))+sqrt((x-2)^(2)+y^(2))=8 is

If (3,4) and (5,12) are the foci of two conics both passing through origin, and the eccentricities of the conics are e_(1) and , e_(2) where e_(1)>e_(2) ,then (4e_(1))/(e_(2)) is equal to

If e_(1) is the eccentricity of the conic 9x^(2)+4y^(2)=36 and e_(2) is the eccentricity of the conic 9x^(2)-4y^(2)=36 then e12-e22=2 b.e22-e12=2c.2 3

If e_1 is the eccentricity of the conic 9x^2+4y^2=36\ a n d\ e_2 is the eccentricity of the conic 9x^2-4y^2=36 then a. e_1 ^2-e_2^ 2=2 b. e_2 ^2-e_1 ^2=2 c. 2 3

The graph of the conic x^(2)-(y-1)^(2)=1 has one tangent line with positive slope that passes through the origin. The point of tangency being (a, b). Q. If e be the eccentricity of the conic, then the value of (1+e^(2)+e^(4)) is

The graph of the conic x^(2)-(y-1)^(2)=1 has one tangent line with positive slope that passes through the origin. The point of tangency being (a, b). Q. If e be the eccentricity of the conic, then the value of (1+e^(2)+e^(4)) is

The graph of the conic x^(2)-(y-1)^(2)=1 has one tangent line with positive slope that passes through the origin. The point of tangency being (a, b). Q. If e be the eccentricity of the conic, then the value of (1+e^(2)+e^(4)) is

Consider the following with regard to eccentricity (e) of conic section 1. e=0 for circle 2. e=1 for parabola 3. elt1 for ellipse Which of the above are correct?

If e, e’ be the eccentricities of two conics S and S’ and if e^2 + e’^2 = 3 , then both S and S’ can be :