In `F(x)=log(c o s e c^(- 1)x)+(x^2-3x+2)/(x^2-2x+1)+sqrt(4[x]-[x]^2)`, where [ . ]= greater integer function, then the largest interval of x for which `F(x)` is defined is

Range of f(x)=[1/(log(x^(2)+e))]+1/sqrt(1+x^(2)), where [*] denotes greatest integer function, is

Range of f(x)=[1/(log(x^(2)+e))]+1/sqrt(1+x^(2)), where [*] denotes greatest integer function, is

Range of f(x)=[1/(log(x^(2)+e))]+1/sqrt(1+x^(2)), where [*] denotes greatest integer function, is

Range of f(x)=[1/(log(x^(2)+e))]+1/sqrt(1+x^(2)), where [*] denotes greatest integer function, is

If f(x)=log((x^(2)-5x+6)/(x^(2)+x+1))+sqrt((1)/([x^(2)-1]))) (Where [.1 is greatest integer),Then domain of function f(x) is

Find range of the function f(x)=log_(2)[3x-[x+[x+[x]]]] (where [.] is greatest integer function)

Find range of the function f(x)=log_(2)[3x-[x+[x+[x]]]] (where [.] is greatest integer function)

Range of the function f(x)=log_(2)[3x-[x+[x+[x+[x]]]] is (where [*] is greatest integer function )

If g(x)=log_(f^(2)(x))((f(x)-1)/(f(x)-2))+(3f(x)-3)^(20)+sin^(-1)((f(x))/(7))+sqrt(cos(sin f(x)))) where f(x) is a real valued function,then the range of f(x) for which g(x) is defined.

The domain of the function f(x)=log_e {sgn(9-x^2)}+sqrt([x]^3-4[x]) (where [] represents the greatest integer function is