6.x=a(theta-sin theta),y=a(1+cos theta)

If x=-a(theta-sin theta),y=a(1-cos theta), then (dy)/(dx) is

The slope of the normal to the curve x=a(theta-sin theta),y=a(1-cos theta) at theta=(pi)/(2)

If x=a(theta-sin theta),y=a(1+cos theta),quad find (d^(2)y)/(dx^(2))

If x=a(theta-sin theta),y=a(1+cos theta) find (d^(2)y)/(dx^(2))

x=a(theta-sin theta),y=a(1+cos theta) find dy/dx

" The area between the cycloid "x=a(theta-sin theta),y=a(1-cos theta),0<=theta<2 pi" and the "x-" axis is "

If x and y are connected parametrically by the equations given,without eliminating the parameter,Find (dy)/(dx)x=a(theta-sin theta),y=a(1+cos theta)

If x and y are connected parametrically by the equation without eliminating the parameter, find (dy/dx) if x=a(theta-sin theta), y=a(1+cos theta)

x= a(theta-sin theta ),y=a(1-cos theta),show that , 2y (d^2y)/(dx^2)+ cosec^2 theta/2=0 .

If x=a(theta+sin theta),y=a(1+cos theta), prove that (d^(2)y)/(dx^(2))=-(a)/(y^(2))