If `x=a(cos theta+logtan(theta/2) and y=a sin theta` then find the value of `(d^2y)/(dx^2)` at `theta=pi/4`.

If x = a (cos theta + log tan(theta/2)) and y = a sin theta , find the value of (d^2y)/(dx^2) at theta = pi/4

If x=a(cos theta+log(tan((theta)/(2))) and y=a sin theta then find the value of (d^(2)y)/(dx^(2)) at theta=(pi)/(4)

If x=a cos^(3)theta and y=a sin^(3)theta, then find the value of (d^(2)y)/(dx^(2)) at theta=(pi)/(6)

If x=2 cos theta-cos 2 theta and y=2 sin theta-sin 2 theta , then the value of (d^(2)y)/(dx^(2)) at theta=(pi)/(2) is -

Find (d^2)/(dx^2) in the following : If x = a cos^3 theta and y = a sin^3 theta , then find the value of d^2y/dx^2) at theta = pi/6

If x=a(cos theta+log tan((theta)/(2))) and y=a sin theta then find (dy)/(dx) at theta=(pi)/(3) and theta=(pi)/(4)

If x = a (cos theta + theta sin theta) and y = a (sin theta - theta cos theta) , find (d^2y)/(dx^2) at t = pi/4 .

If x = a(cos theta + log tan(theta/2)), y = a sin theta find dy/dx at theta = pi/3

If x sec theta , y = tan theta , then the value of (d^(2) y)/(dx^(2)) " at " theta = (pi)/(4) is