Home
Class 12
PHYSICS
[" 4.From the top of a tower,a particle ...

[" 4.From the top of a tower,a particle is thrown vertically "],[" downwards with a velocity of "10m/s" .The ratio of the "],[" distances,covered by it in the "3rd" and "2nd" seconds of the "],[" motion is (Take "g=10m/s^(2))],[[" (a) "5:7," (b) "7:5],[" (c) "3:6," (d) "6:3]]

Promotional Banner

Similar Questions

Explore conceptually related problems

From the top of a tower, a particle is thrown vertically downwards with a velocity of 10 m//s . The ratio of the distances, covered by it in the 3rd and 2nd seconds of the motion is ("Take" g = 10 m//s^2) .

From the top of a tower, a particle is thrown vertically downwards with a velocity of 10 m//s . The ratio of the distances, covered by it in the 3rd and 2nd seconds of the motion is ("Take" g = 10 m//s^2) .

A ball is thrown vertically downward with a velocity of 20m/s from the top of a tower,It hits the ground after some time with a velocity of 80m/s .The height of the tower is : (g=10m/g^(2))

If a ball is thrown vertically upwards with a velocity of 40m//s , then velocity of the ball after 2s will be (g = 10m//s^(2))

If a ball is thrown vertically upwards with a velocity of 40m//s , then velocity of the ball after 2s will be (g = 10m//s^(2))

A body is thrown vertically upward with velocity u. The distance travelled by it in the 7^(th) and 8^(th) seconds are equal. The displacement in 8^(th) seconds is equal to (take g=10m//s^(2) )

A body is thrown vertically upward with velocity u. The distance travelled by it in the 7^(th) and 8^(th) seconds are equal. The displacement in 8^(th) seconds is equal to (take g=10m//s^(2) )

A particle is thrown vertically upwards its velocity at half of the height is 10 m/s then the maximum height attained by it is ( g= 10 m//s^2)

A stone is thorwn vertically upwards with initial velocity of 40m//s . Taking g=10m//s^2 find the maximum height and total distance covered by stone