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" 13."(x^(2)+y^(2))^(2)=xy...

" 13."(x^(2)+y^(2))^(2)=xy

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If x=2+3i and y=2-3i then find the values of : (x^(2)+xy+y^(2))/(x^(2)-xy+y^(2))

Simplify: 2x^(2)+3xy -3y^(2)+x^(2)-xy+y^(2)

The middle terms of ((x^(3//2)y)/(2)+(2)/(xy^(3//2)))^13 are

solve: -2 (x^(2) - y^(2) + xy) - 3 (x^(2) + y^(2) - xy)

Simplify : (x^(2) - y^(2) + 2xy + 1) - (x^(2) + y^(2) + 4xy - 5)

Find the continued product of x+y,x-y,x^(2)+xy+y^(2),x^(2)-xy+y^(2)

x-x^(2)y+xy^(2)-y

Subtract: 13x^(2)-2y^(2)+5xy from 3x^(2)+4xy^(4)-8y^(2) hosizontally.