" 1."(8x-3)/(3x)=2

Solve for x: (8x-1)/2+3x-4=(1+2x)/3

If (8/3)^(3-x) = (3/8 )^(2x-1) , then x =

If y=tan^(-1)((4x)/(1-5x^(2)))+tan^(-1)((3+8x)/(8-3x)) , then (dy)/(dx) is :

(2^((3x-1)/(x-1)))^((1)/(3))<8^((x-3)/(3x-7))

Find lim_(x rarr oo) ((1-2x)/(1+8x^3)^(1/3) +2^(-x^7))

Find underset( x rarr oo )("lim") ((1-2x)/((1+ 8x^(3))^(1//3))+2^(-x^(7)))

If x^2-3x-1=0 , then the value of (x^2+ 8x-1)(x^3+x^(-1))^-1 is: यदि x^2-3x-1=0 है, तो (x^2+ 8x-1)(x^3+x^(-1))^-1 का मान क्या होगा ?

If x is so small that x^3 and higher powers of x may be neglected, then ((1+x)^(3/2)-(1+1/(2x))^3)/((1-x)^(1/2)) may be approximated as A. 3x+3/8x^2 B. 1-3/8x^2 C. x/2-3/x^2 D. -3/8x^2