Let p be a prime number such that `p>=3`. Let `n=p!+1`. The number of primes in the list `n+1`, `n+2, n+3, ......n+p -1` is

Let p be a prime number such that 3

If 'P' is a prime number such that p ge 23 and n+ p! + 1 , then the number of primes in the list n+ 1, n+2 , ….. , n+p-1 is

Let p be prime number such that 3 < p < 50 , then p^2 - 1 is :

Let P(n): n^(2)-n+41 is a prime number, then

Let A=P_(n)!+1. where p_(n) is the n^(th) prime number.The probability that number picked at random from the sequence A+1,A+2,......A+n is a prime number is (A) 0 (B) 1 (C) (n)/(A) (D) (n!)/(A)

Let p be a prime number and n be a positive integer then exponent of p in n! is denoted by ^E_p(n! ) and is given by E_p(n!)=[n/p]+[n/(p)^2]+[n/(p)^3]+....[n/(p^k)] where p^kltnltp^(k+1) and [x] denotes the greatest integral part of x if we isolate the power of each prime contained in any number N then N can be written as N=2^(alpha_1).3^(alpha_2).5^(alpha_3).7^(alpha_4) ....where alpha_i are whole numbers The number of zeros at the end of 108! is

Let p be a prime number and n be a positive integer then exponent of p in n! is denoted by E_p(n!) and is given by E_p(n!)=[n/p]+[n/(p)^2]+[n/(p)^3]+....[n/(p^k)] where p^kltnltp^(k+1) and [x] denotes the greatest integral part of x if we isolate the power of each prime contained in any number N then N can be written as N=2^(alpha_1).3^(alpha_2).5^(alpha_3).7^(alpha_4) ....where alpha_i are whole numbers the exponent of 7 in ,^100c_50 is

If M is even prime number,N is least prime number of two digits & P is greatest prime number of two digits, then (P+N)/(M) is dividible by-

If M is even prime number,N is least prime number of two digits & P is greatest prime number of two digits, then (P+N)/(M) is dividible by-