(d)/(dx)tan^(-1)[(cos x-sin x)/(cos x+sin x)]

If f (x) = tan ^(-1) ((cos x- sinx)/(cos x+ sin x)) then the value of (d)/(dx) f(x) is-

Differentiate the following w.r.t x tan^(-1) ((cos x - sin x)/(cos x + sin x))

Differentiate the following w.r.t.x. tan^(-1)((cos x - sin x)/(cos x + sin x))

Differentiate tan^(-1) frac((cos x-sin x))((cos x+ sin x))

Differentiate 'tan^(^^)(-1){(cos x+sin x)/(cos x-sin x)},|-pi/4

d/(dx)(tan^(-1) ((cos x)/(1+sinx)) =

Differentiate, tan^(-1) ((a cos x- b sin x)/(b cos x + a sin x)), (-pi)/(2) lt x lt (pi)/(2) and (a)/(b) tan x gt -1

d/dx tan^(-1) ((cosx )/(1+sin x)) =

Find (d)/(dx) tan^(-1)(sqrt((1-cos x)/(1+cos x))) .

A: (d)/(dx ) {Tan ^(-1) ((a cos x + b sin x)/(b cos x - a sin x))=1 R: (d)/(dx) {Tan ^(-1) ((a cos f (x) +b sin f (x))/(b cos f (x) -a sin f (x)))}=f'(x)