A solution containing `Na_(2)CO_(3)` and `NaOH` requires `300 ml` of `0.1 N HCl` using phenolphthalein as an indicator. Methyl orange is then added to the above titrated solution when a further `25 ml` of `0.2 N HCl` is required. The amount of `NaOH` present in solution is `(NaOH=40, Na_(2)CO_(3)=106)`

0.1g of a solution containing Na_(2)CO_(3) and NaHCO_(3) requires 10mL of 0.01 N HCl for neutralization using phenolphthalein as an indicator, mass% of Na_(2)CO_(3) in solution is:

0.1g of a solution containing Na_(2)CO_(3) and NaHCO_(3) requires 10mL of 0.01 N HCl for neutralization using phenolphthalein as an indicator, mass% of Na_(2)CO_(3) in solution is:

A solution contains Na_(2)CO_(3) and NaHCO_(3). 10 mL of the solution required 2.5 mL "of" 0.1M H_(2)SO_(4) for neutralisation using phenolphthalein as indicator. Methyl orange is then added when a further 2.5 mL "of" 0.2M H_(2)SO_(4) was required. The amount of Na_(2)CO_(3) and NaHCO_(3) in 1 "litre" of the solution is:

A solution contains Na_(2)CO_(3) and NaHCO_(3). 10 mL of the solution required 2.5 mL "of" 0.1M H_(2)SO_(4) for neutralisation using phenolphthalein as indicator. Methyl orange is then added when a further 2.5 mL "of" 0.2M H_(2)SO_(4) was required. The amount of Na_(2)CO_(3) and NaHCO_(3) in 1 "litre" of the solution is: