`(p^2-3/2q^2)^3`

Let's resolve into factors: (p^2 - 3q^2)^2 - 16 (p^2 - 3q^2) + 63

If p=cot theta +tan theta and q=sec theta -cos theta then (p^(2)q)^((2)/(3))-(q^(2)p)^((2)/(3)) is equal to

write the degree of the polynomial p^(2)q^(3)+p^(3)q^(2)-p^(3)q^(3) .

Find the value of 2p^2q-3pq^2+2p-3p+1 when p=3,q=-3

{(p^(2)+3px+3pq+9qx)(p-3q)}-:(p^(2)-9q^(2))

Let p and q be real numbers such that p!=0,p^3!=q ,and p^3!=-qdot If alpha and beta are nonzero complex numbers satisfying alpha+beta=-p and alpha^3+beta^3=q , then a quadratic equation having alpha//beta and beta//alpha as its roots is A. (p^3+q)x^2-(p^3+2q)x+(p^3+q)=0 B. (p^3+q)x^2-(p^3-2q)x+(p^3+q)=0 C. (p^3+q)x^2-(5p^3-2q)x+(p^3-q)=0 D. (p^3+q)x^2-(5p^3+2q)x+(p^3+q)=0

Let p and q be real numbers such that p!=0,p^3!=q ,and p^3!=-qdot If alpha and beta are nonzero complex numbers satisfying alpha+beta=-p and alpha^3+beta^3=q , then a quadratic equation having alpha//beta and beta//alpha as its roots is A. (p^3+q)x^2-(p^3+2q)x+(p^3+q)=0 B. (p^3+q)x^2-(p^3-2q)x+(p^3+q)=0 C. (p^3+q)x^2-(5p^3-2q)x+(p^3-q)=0 D. (p^3+q)x^2-(5p^3+2q)x+(p^3+q)=0

Let pa n dq be real numbers such that p!=0,p^3!=q ,a n d p^3!=-qdot If alphaa n dbeta are nonzero complex numbers satisfying alpha+beta=-pa n dalpha^2+beta^2=q , then a quadratic equation having alpha//betaa n dbeta//alpha as its roots is A. (p^3+q)x^2-(p^3+2q)x+(p^3+q)=0 B. (p^3+q)x^2-(p^3-2q)x+(p^3+q)=0 C. (p^3+q)x^2-(5p^3-2q)x+(p^3-q)=0 D. (p^3+q)x^2-(5p^3+2q)x+(p^3+q)=0

Let pa n dq be real numbers such that p!=0,p^3!=q ,a n d p^3!=-qdot If alphaa n dbeta are nonzero complex numbers satisfying alpha+beta=-pa n dalpha^3+beta^3=q , then a quadratic equation having alpha//betaa n dbeta//alpha as its roots is A. (p^3+q)x^2-(p^3+2q)x+(p^3+q)=0 B. (p^3+q)x^2-(p^3-2q)x+(p^3+q)=0 C. (p^3+q)x^2-(5p^3-2q)x+(p^3-q)=0 D. (p^3+q)x^2-(5p^3+2q)x+(p^3+q)=0