`(3x^2+y-3)^2`

Simplify (x-2y+3)^2+(x+2y-3)^2

Simplify : (x-2y+3)^2+(x+2y-3)^2

Show that x^3-3x y^2=(-2) and 3x^2\ y-y^3=2 intersect orthogonally.

Show that x^3-3x y^2=-2 and 3x^2\ y-y^3=2 intersect orthogonally:

((x +y)^(3) + (x-y)^(3))/(2) -y (3x^(2) + y^(2)) = ______

The equation of the transvers and conjugate axes of a hyperbola are, respectively, x+2y-3=0 and 2x-y+4=0 , and their respective lengths are sqrt(2) and 2sqrt(3)dot The equation of the hyperbola is 2/5(x+2y-3)^2-3/5(2x-y+4)^2=1 2/5(x-y-4)^2-3/5(x+2y-3)^2=1 2(2x-y+4)^2-3(x+2y-3)^2=1 2(x+2y-3)^2-3(2x-y+4)^2=1

Find dy/dx if x^3+2x^2y+3xy^2+4y^3=5

(3x - 2y)^2 - (3x - 2y)^2 = ___

Factorize: (3x-2y)^3+(2y-4z)^3+(4z-3x)^3