If `P_(n)` denotes the product of first n natural numbers, then for all `n inN.`

The product of first n odd natural numbers equals:

If the mean of first n natural numbers is 11 then n =

Find the sum of the products of first n natural numbers, taken two at a time.

Find the sum of of the products of first n natural numbers, taken two at a time .

Let X_(n) denote the mean of first n natural numbers, then the mean of X_(1), X_(2), ………….., X_(100) is

Let X_(n) denote the mean of first n natural numbers, then the mean of X_(1), X_(2), ………….., X_(100) is

Let S_(n) denote the sum of the cubes of the first n natural numbers and s_(n) denote the sum of first n natural numbers then (S_(n))/(s_(n)) is equal to (i) (n(n+1)(n+2))/6 (ii) (n( n+1))/2 (iii) (n^(2)+3n+2)/2 (iv) (2n+1)/3