" If "a,b," chave the same sign,then "cot^(-1)((oo^(b)+1)/(a-b))+cot^(-1)((bc+1)/(b-c))+cot^(-1)((cos+1)/(c-alpha))

Prove that: cot^(-1)((ab+1)/(a-b))+cot^(-1)((bc+1)/(b-c))+cot^(-1)((ca+1)/(c-a))=0

Prove that: cot^(-1)((ab+1)/(a-b))+cot^(-1)((bc+1)/(b-c))+cot^(-1)((ca+1)/(c-a))=0 .

Id a,b,c are distinct non-zero real numbers having the same sign. Prove that Cot^(-1)((ab+1)/(a-b)) +cot^(-1)((bc+1)/(b-c))+ Cot^(-1)((ca+1)/(c-a)) = pi (or) 2 pi .

Prove that : cot^(-1)((1+ab)/(a-b))+cot^(-1)((1+bc)/(b-c))+cot^(-1)((1+ca)/(c-a))=pi,(a>b>c>0)

Prove that : cot^(-1)((1+ab)/(a-b))+cot^(-1)((1+bc)/(b-c))+cot^(-1)((1+ca)/(c-a))=pi,(a>b>c>0)

If a > b > c >0 , prove that cot^(-1)((a b+1)/(a-b))+cot^(-1)((b c+1)/(b-c))+cot^(-1)((c a+1)/(c-a))=pi

If a > b > c >0 , prove that cot^(-1)((a b+1)/(a-b))+cot^(-1)((b c+1)/(b-c))+cot^(-1)((c a+1)/(c-a))=pi

If ab gt -1, bc gt -1 and ca gt -1 , then the value of cot^(-1) ((ab+1)/(a-b) ) + cot^(-1) ((bc+1)/(b-c) ) + cot^(-1) ((ca+1)/( c-a)) is a) -1 b) cot^(-1) "" (a+b+c) c) cot^(-1) ("abc") d)0

If a