" Vector which is perpendicular to "(a cos theta i+b sin theta j)

Vectors which is perpendicular to ( a cos theta hat (i) + b sin theta hat(j)) is

Find the equation of the straight line through (a cos theta, b sin theta) perpendicular to the line x/(a cos theta)+ y/(b sin theta) = 1 .

Find the equation of the straight line through (a cos theta, b sin theta) perpendicular to the line x/(a cos theta)+ y/(b sin theta) = 1 .

Find the general value of theta which satisfies the equation (cos theta+i sin theta)(cos2 theta+i sin2 theta)......(cos n theta+i sin n theta)=1

Given: vec(A)=Acos theta hat(i)+Asin theta hat(j) . A vector vec(B) , which is perpendicular to vec(A) ,is given by

.If x+(1)/(x)=2cos theta ,then x is equal to (A) cos theta+i sin theta, (B) cos theta-i sin theta, (C) cos theta+-i sin theta, (D) sin theta+-i cos theta

Area of a triangle whose vertices are (a cos theta, b sin theta) , ( - a sin theta , b cos theta) " and " ( - a cos theta, - b sin theta) is

If theta is an acute angle and the vector (sin theta)hat i+(cos theta)hat j is perpendicular to the vector hat i-sqrt(3)hat j, then theta=(pi)/(6) b.(pi)/(5) c.(pi)/(4)d(pi)/(3)

If ' theta ' is an acute angle and the vector (sin theta)bari +(cos theta)bari " is perpendicular to the vector " bari -sqrt3barj , " then " theta =

Eliminate theta between the equation : x =a cos theta + b sin theta, y =a sin theta- b cos theta .