If the sides of a triangle are `ax^2+2hxy+by^2=0` and `y=x+c` , then the area is

The equation of the sides of a triangle are x+2y+1=0, 2x+y+2=0 and px+qy+1=0 and area of triangle is Delta .

The equation of the sides of a triangle are x+2y+1=0, 2x+y+2=0 and px+qy+1=0 and area of triangle is Delta .

If a + b = 2h , then the area of the triangle formed by the lines ax^(2) + 2hxy + by^(2) = 0 and the line x-y+2=0, in sq. units, is

If a+b=2h, then the area of the triangle formed by the lines ax^(2)+2hxy+by^(2)=0 and the line x-y+2=0, in sq.units is

If the pair of lines ax^2 +2hxy+ by^2+ 2gx+ 2fy +c=0 intersect on the y-axis then

If the pair of lines ax^2 +2hxy+ by^2+ 2gx+ 2fy +c=0 intersect on the y-axis then

If the pair of lines ax^2 +2hxy+ by^2+ 2gx+ 2fy +c=0 intersect on the y-axis then

Show that the centroid (x',y') of the triangle with sides ax^2+2hxy+by^2=0 and lx +my =1, is given by (x')/(bl-hm)=(y')/(am-hl)=(2)/(3(am^2-2hlm+bl^2))

Show that the area of the triangle formed by the lines ax^2+2hxy+by^2=0 and lx+my+n=0 is (n^2sqrt((h^2-ab)))/(|(am^2-2hlm+bl^2)|)

Show that the area of the triangle formed by the lines ax^2 + 2hxy + by^2 = 0 and lm + my + n =0 is (n^2 sqrt(h^2 - ab))/(|am^2 - 2hlm + bl^2|)