`2 Omega, 3 Omega` तथा `6 Omega` के तीन प्रतिरोधकों को किस प्रकार सयोंजित करेंगे कि संयोजन का कुल प्रतिरोध a) `4 Omega`, b) `1 Omega` हो?

How can three resistors of resistances 2 Omega, 3 Omega , and 6 Omega be connected to give a total resistance of (a) 4 Omega , (b) 1 Omega ?

How can three resistors of resistances 2 Omega,3 Omega , and 6 Omega be connected to give a total resistance of (a) 4 Omega (b) 1 Omega ?

How can three resistors of resistances 2 Omega,3 Omega , and 6 Omega be connected to give a total resistance of (a) 4 Omega (b) 1 Omega ?

How can three resistors of resistance 2 Omega 3 Omega and 6 Omega be connected to give a total resistance of (a) 4 Omega (b) 1 Omega ?

(1-omega +omega^2)(1+omega-omega^2)=4

If 1 , omega + omega^(2) are the cube roots of unity prove that (i) (1 - omega + omega^(2))^(6) + (1 - omega^(2) + omega)^(6) = 128 = ( 1 - omega + omega^(2))^(7) + ( 1 + omega - omega^(2))^(7) (ii) ( a+ b) ( aomega+b omega^(2))( a omega^(2) + b omega) = a^(3) + b^(3) (iii) x^(2) + 4x + 7 = 0 " where " x = omega - omega^(2) - 2 .