Two bodies of masses `m_1` and `m_2` are moving with velocity `v_1` and `v_2` respectively in the same direction. The total momentum of the system in the frame of reference attached to the centre of mass is (`v` is relative velocity between the masses)

Two bodies A and B of same mass are moving with velocities v and 2v, respectively. Compare their momentum.

Two bodies A and B of same mass are moving with velocities v and 2v, respectively. Compare their inertia

Two balls A and B of masses m and 2 m are in motion with velocities 2v and v, respectively. Compare: Their momentum.

Two masses, m_(1) and m_(2) , are moving with velocities v_(1) and v_(2) . Find their total kinetic energy in the reference frame of centre of mass.

Two masses, m_(1) and m_(2) , are moving with velocities v_(1) and v_(2) . Find their total kinetic energy in the reference frame of centre of mass.

Two particles having masses m_(1) and m_(2) are moving with velocities vec(V)_(1) and vec(V)_(2) respectively. vec(V)_(0) is velocity of centre of mass of the system. (a) Prove that the kinetic energy of the system in a reference frame attached to the centre of mass of the system is KE_(cm) = (1)/(2)mu V_(rel)^(2) . Where mu=(m_(1)m_(2))/(m_(1)+m_(2)) and V_(rel) is the relative speed of the two particles. (b) Prove that the kinetic energy of the system in ground frame is given by KE=KE_(cm)+(1)/(2)(m_(1)+m_(2))V_(0)^(2) (c) If the two particles collide head on find the minimum kinetic energy that the system has during collision.