=(2^(2)times3^(3)times5^(4))" and "b=(2^(3)times3^(2)times5)," then "HCF(a,l]

(5^(-3)times a^(3)times c^(4))/(5^(2)times a^(-4)times c^(3))

(4^(5)times a^(8)times b^(3))/(4^(5)times a^(5)times b^(2))

(2^(2)times3^(4)times4)/(3times32),

If a= ( 2^(2) xx 3^(3) xx 5^(4)) and b = (2^(3) xx 3^(2) xx 5) then HCF (a, b) ?

A real number (2^(2)times3^(2)times7^(2))/(2^(2)times5^(3)times3^(5)times7^(4)) will have

((5^(3))^(-2)times(5^(2))^(-3)times(6)^(5))/((2)^(3)times(3)^(2)times(5)^(5))

What is the HCF of 2^(3)times7^(2) and 2^(5)times3^(1) ?

5(1)/(7)times3(2)/(4)

solve it : (ii) (-3)/(5)times(-3)/(5)times(-3)/(5)times(-3)/(5) (iii) (-9)/(2)times(4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2) (iv) (-5)/(3)times(-5)/(3)times(-5)/(3)times(-5)/(3) (v) (-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)

Simplify (3^(-5)times5^(-7)times(-2)^(3))/(3^(4)times5^(-2)times(-2)^(-3))