Let `f(x)=sinx+2cos^2x`, x `in [pi/6,(2pi)/3]`, then maximum value of f(x) is

Let f(x)=sinx+2cos^2x,pi/4lexle(3pi)/4 . then f attains its

Let f(x)=|x|+|sinx|, x in (-pi/ 2,3pi/2). Then , f is

Let f(x)=(cos x -sinx)/(cos 2x)+ sin^2x , x ne pi/4 . The value of f(pi//4) so that f is continuous on (0,pi//2) is (sqrt2=1.41)

Let f(x)=2cos ec2x+sec x+cos ecx, then the minimum value of f(x) for x in(0,(pi)/(2)) is

If f(x) = 2 sinx, g(x) = cos^(2) x , then the value of (f+g)((pi)/(3))

If f(x) = 2 sinx, g(x) = cos^(2) x , then the value of (f+g)((pi)/(3))

Let f(x)=sinx+2cos^(2)x,(pi)/(4)lexle(3pi)/(4) . Then f attains its-

Let f be a function defined on [-(pi)/(2), (pi)/(2)] by f(x) = 3 cos^(4) x-6 cos^(3) x - 6 cos^(2) x-3 . Then the range of f(x) is

The function f(x)=(sinx)^(tan^(2)x) is not defined at x=(pi)/(2) . The value of f((pi)/(2)) such that f is continuous at x=(pi)/(2) is