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Solve: 2/3 x+1=7/3....

Solve: `2/3 x+1=7/3`.

A

`5`

B

`4`

C

`3`

D

`2`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the equation \( \frac{2}{3}x + 1 = \frac{7}{3} \), we will follow these steps: ### Step 1: Isolate the term with \( x \) We start with the equation: \[ \frac{2}{3}x + 1 = \frac{7}{3} \] To isolate the term with \( x \), we need to move \( 1 \) to the right side of the equation. We do this by subtracting \( 1 \) from both sides: \[ \frac{2}{3}x = \frac{7}{3} - 1 \] ### Step 2: Convert \( 1 \) to a fraction with a common denominator Next, we need to express \( 1 \) as a fraction with a denominator of \( 3 \): \[ 1 = \frac{3}{3} \] Now we can rewrite the equation: \[ \frac{2}{3}x = \frac{7}{3} - \frac{3}{3} \] ### Step 3: Subtract the fractions Now we perform the subtraction on the right side: \[ \frac{2}{3}x = \frac{7 - 3}{3} = \frac{4}{3} \] ### Step 4: Eliminate the fraction To eliminate the fraction, we can multiply both sides of the equation by \( \frac{3}{2} \) (the reciprocal of \( \frac{2}{3} \)): \[ x = \frac{4}{3} \cdot \frac{3}{2} \] ### Step 5: Simplify the right side Now we simplify the right side: \[ x = \frac{4 \cdot 3}{3 \cdot 2} = \frac{4}{2} = 2 \] ### Final Answer Thus, the solution to the equation is: \[ x = 2 \] ---
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RS AGGARWAL-LINEAR EQUATIONS-TEST PAPER-8 (D) (Write .T. for true and .F. for false for each of the following:)
  1. Solve: 2/3 x+1=7/3.

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  2. Write 'T' for true and 'F' for false for each of the following: (i)(5 ...

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