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the denominator of a rational number is greater than its numerator by `3`. If `3` is subtracted from the numerator and `2` is added to its denominator, the new number becomes `1/5`. Find the original number. Check your solution.

A

`5/8`

B

`3/8`

C

`7/8`

D

`9/8`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will define the variables and set up the equations based on the information provided. ### Step 1: Define the variables Let the numerator of the rational number be \( x \). Then, the denominator will be \( x + 3 \) (since the denominator is greater than the numerator by 3). ### Step 2: Set up the equation According to the problem, if 3 is subtracted from the numerator and 2 is added to the denominator, the new fraction becomes \( \frac{1}{5} \). This gives us the equation: \[ \frac{x - 3}{(x + 3) + 2} = \frac{1}{5} \] This simplifies to: \[ \frac{x - 3}{x + 5} = \frac{1}{5} \] ### Step 3: Cross-multiply to eliminate the fraction Cross-multiplying gives us: \[ 5(x - 3) = 1(x + 5) \] ### Step 4: Expand both sides Expanding both sides results in: \[ 5x - 15 = x + 5 \] ### Step 5: Rearrange the equation Now, we will move all terms involving \( x \) to one side and constant terms to the other side: \[ 5x - x = 5 + 15 \] This simplifies to: \[ 4x = 20 \] ### Step 6: Solve for \( x \) Dividing both sides by 4 gives: \[ x = 5 \] ### Step 7: Find the original rational number Now that we have the numerator, we can find the denominator: \[ \text{Denominator} = x + 3 = 5 + 3 = 8 \] Thus, the original rational number is: \[ \frac{5}{8} \] ### Step 8: Check the solution To verify, we will substitute \( x = 5 \) back into the conditions of the problem: 1. Subtracting 3 from the numerator: \[ 5 - 3 = 2 \] 2. Adding 2 to the denominator: \[ 8 + 2 = 10 \] 3. The new fraction becomes: \[ \frac{2}{10} = \frac{1}{5} \] This matches the condition given in the problem, confirming our solution is correct. ### Final Answer The original rational number is \( \frac{5}{8} \). ---
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