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(9x)/(7-6x)=15...

`(9x)/(7-6x)=15`

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(9x)/(7-6x)=2

Solve for x : (7-6x)/(9x)=(1)/(15)

Solve (7-6x)/(9x)=(1)/(15)

(9x-5)/(7)=(6x+2)/(5)

(9x-7)/(3x+5)=(3x-4)/(x+6) then, x=?

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Find the intervals in which f(x)=x^(3)-6x^(2)+9x+15 is increasing or decreasing.

lim_(x rarr oo)(9x^(2)-2x-7)/(6x^(2)+5x+1

6(3x+2)-5(6x-1)=3(x-8)-5(7x-6)+9x