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RS AGGARWAL-LINEAR EQUATIONS-EXERCISE 8A
- (x-5)/2 - (x-3)/5 = 1/2
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- (3t-2)/4 - (2t+3)/3 = 2/3 -t
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- (2x+7)/5 - (3x+11)/2 = (2x+8)/3 -5
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- solve (5x-4)/6 = 4x + 1 -(3x+10)/2
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- 5x-1/3(x+1)=6(x+1/30)
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- 4-(2(z-4))/3=1/2(2z+5)
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- (3(y-5))/4-4y=3-(y-3)/2
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- (8x-3)/(3x)=2
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- (9x)/(7-6x)=15
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- (3x)/(5x+2)=-4
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- (6y-5)/(2y)=7/9
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- (2-9z)/(17-4z)=4/5
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- (4x+7)/(9-3x)=1/4
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- (7Y + 4)/(Y+2)=(-4 )/(3)
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- (15(2-y)-5(y+6))/(1-3y)=10
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- (2x-(7-5x))/(9x-(3+4x))=7/6
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- m-(m-1)/2=1-(m-2)/3
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- (3x+5)/(4x+2)=(3x+4)/(4x+7)
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- (9x-7)/(3x+5)=(3x-4)/(x+6)then, x=?
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- (2-7x)/(1-5x)=(3+7x)/(4+5x)
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