A particle is projected up with an initial velocity of `80 ft//sec`. The ball will be at a height of 96ft from the ground after

A ball is thrown vertically upward from the top of a building 96feet tall with an initial velocity of 80feet per second. The distance S (in feet )of the ball from the ground, after t seconds is S = 96 + 80t − 16t^(2) . After how many seconds does the ball strike the ground.

An object is thrown upward with a vertical velocity of 128 ft./sec. It will return in

An object is thrown upward with a vertical velocity of 128 ft./sec. It will return in

A particle A is projected from the ground with an initial velocity of 10m//s at an angle of 60^(@) with horizontal. From what height should an another particle B be projected horizontally with velocity 5m//s so that both the particles collide in ground at point C if both are projected simultaneously g=10 m//s^(2) .

A particle A is projected from the ground with an initial velocity of 10m//s at an angle of 60^(@) with horizontal. From what height should an another particle B be projected horizontally with velocity 5m//s so that both the particles collide in ground at point C if both are projected simultaneously g=10 m//s^(2) .

The height of a ball thrown into the air with an initial vertical velocity of 24 fts from a height of 6 feet above the ground is given by the equation: h=16t^(2)+24t+6, where t is the time in seconds,for the ball has been in air. After how many seconds is the ball at a height of 14 feets

A boy of height 4 ft walking horizontally with a uniform velocity of 2m/s passes under a bulb which is at a height of 12ft above the ground.The velocity of edge of the shadow of the boy's head (in m/s) is?

A particle is projected from ground with speed u and at an angle theta with horizontal. If at maximum height from ground, the speed of particle is 1//2 times of its initial velocity of projection, then find its maximum height attained.

A particle is projected from ground with speed u and at an angle theta with horizontal. If at maximum height from ground, the speed of particle is 1//2 times of its initial velocity of projection, then find its maximum height attained.