when the voltage applied to an X-ray tube increases from `V_(1) = 10 kV to V_(2) = 20 kV`, the wavelenght interval between K_(alpha)` line and cut-off wavelenght of continuous spectrum increases by a factor of `3`. Atomic number of the metallic target is

When the voltage applied to an X-ray tube increases from V_(1) = 10 kV to V_(2) = 20 kV , the wavelength interval between K_(a) line and cut-off wavelength of continuous spectrum increase by a factor of 3. Atomic number of the metalic target is

When the voltage applied to an X-ray tube increased from V_(1)=15.5kV to V_(2)=31kV the wavelength interval between the K_(alpha) line and the cut-off wavelength of te continuous X-ray spectrum increases by a factor of 1.3 . If te atomic number of the element of the target is z. Then the value of (z)/(13) will be: (take hc=1240eVnm and R=1xx(10^(7))/(m))

When the voltage applied to an X-ray tube increased from V_(1)=15.5kV to V_(2)=31kV the wavelength interval between the K_(alpha) line and the cut-off wavelength of te continuous X-ray spectrum increases by a factor of 1.3 . If te atomic number of the element of the target is z. Then the value of (z)/(13) will be: (take hc=1240eVnm and R=1xx(10^(7))/(m))

When the voltage applied to an X-ray tube increases from 10 to 20 kV the wavelength difference between the ka line and the short wave cut-off of continuous X-ray spectrum increases by a factor of 3.0 . Identify the target element. Take 4/3R = 1200 Å where R is Rydberg’s contant and hc = 12.4 keV Å

If voltage applied to X -ray tube increased from V=10kV to 20kV . The wave length interval between K_(alpha)- line and short wave cut off continuous X -ray increases by factor of 3 (Rhc)/e=13.6V where R is Rydberg constant h is plank's constant c is speed of light in vacuum and e is charge on electron