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Initial velocity of the block vecu=45hat...


Initial velocity of the block `vecu=45hati` while external force on it is `vecF=25(-hati)` it coefficient of static and kinetic friction are 0.3 and 0.2 respectively then distance travelled by the block in 12 sec `(g=10m//s^(2))`

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A block of mass 20kg is pushed with a horizontal force of 90N . It the coefficient of static and kinetic friction are 0.4 and 0.3, the frictional force acting on the block is (g =10ms^(-2)) .

A block of mass 20kg is pushed with a horizontal force of 90N. If the coefficient of static & kinetic friction are 0.4 & 0.3, the frictional force acting on the block is: (g =10ms^(-2) )

A block of mass 20kg is pushed with a horizontal force of 90N. If the coefficient of static & kinetic friction are 0.4 & 0.3, the frictional force acting on the block is: (g =10ms^(-2) )