`P` is a point within or on the circle `x^2 + y^2 = r^2.` The probability that the point P is such that it is above the line `y = mx` is

A variable point P is on the circle x^2 + y^2 =1 on xy plane. From point P, perpendicular PN is drawn to the line x =y =z then the minimum length of PN is:-

If the line y=mx+asqrt(1+m^2) touches the circle x^2+y^2=a^2 , then the point of contact is

If the line y=mx+c be a tangent to the circle x^2+y^2=a^2 , then the point of contact is

A square is incribed in a circle . If p_(1) is the probability that a randomly chosen point of the circle lies within the square and p_(2) is the probability that the point lies outside the square then

A square is incribed in a circle . If p_(1) is the probability that a randomly chosen point of the circle lies within the square and p_(2) is the probability that the point lies outside the square then

The straight-line y= mx+ c cuts the circle x^(2) + y^(2) = a^(2) in real points if :

The straight-line y= mx+ c cuts the circle x^(2) + y^(2) = a^(2) in real points if :

Let P be a point on the circle x^(2)+y^(2)=9 , Q a point on the line 7x+y+3=0 , and the perpendicular bisector of PQ be the line x-y+1=0 . Then the coordinates of P are

A square is inscribed in a circle.If p_(r) is the probability that a randomly chosen point inside the circle lies within the square and p, is the probability that the point lies outside the square,then