Let A be the sum of the first 20 terms and B be the sum of the first 40 terms of the series `1^2+2.2^2+3^2+2.4^2+5^2+2.6^2+...` If `B-2A=100lambda` then `lambda` is equal to (1) 232 (2) 248 (3) 464 (4)496

Let A be the sum of the first 20 terms and B be the sum of the first 40 terms of the series 1^(2)+2.2^(2)+3^(2)+2.4^(2)+5^(2)+2.6^(2)+... If B-2A=100 lambda then lambda is equal to (1)232(2)248 (3) 464 (4) 496

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