What is the final temperature of `0.10` mole monoatomic ideal gas that performs `75 cal` of work adiabatically.if the initial temperature is `227 ^(@)C` ( use `R=2 cal //K-mol)`

Calculate the final temperature of a monoatomic ideal gas that is compressed reversible and adiabatically from 16L to 2L at 300 K :

Calculate the final temperature of a monoatomic ideal gas that is compressed reversible and adiabatically from 16L to 2L at 300 K :

The initial temperature of a two mole monoatomic gas is T. If temperature increases to 3T then work done in the adiabatic process is

An ideal monoatomic gas at 300K expands adiabatically to twice its volume. What is the final temperature?

An ideal monoatomic gas at 300K expands adiabatically to twice its volume. What is the final temperature?

When 1 mole of an ideal monatomic gas is compressed adiabatically the intenal energy change involved is 24 cals. The temperature rise is

When "1" mole of an ideal monoatomic gas is compressed adiabatically the internal energy change involved is "24 cals.The temperature rise is

Five moles of an ideal monoatomic gas with an initial temperature of 150^@C expand and in the process absorb 1500 J of heat and does 2500 J of work. The final temperature of the gas in .^@C is (ideal gas constant R = 8.314 J K^(-1)mol^(-1))